What is (6+2i)/(i)?

Multiply the numerator and denominator by $i$: $\frac{(6+2i)i}{i\cdot i}=\frac{6i+2i^2}{i^2}=\frac{6i-2}{-1}=2-6i$, choice H. Equivalently, since $\frac{1}{i}=-i$, the quotient is $(6+2i)(-i)=-6i-2i^2=-6i+2=2-6i$. Choice G ($2+6i$) loses the sign of the imaginary part. Choice J ($-2+6i$) has both signs reversed, which happens if you forget to divide by $-1$. Choice F ($6+2i$) is the original numerator and was not divided at all. Check by multiplying the answer by $i$: $(2-6i)i=2i+6=6+2i$. Dividing by $i$ is the same as multiplying by $-i$.