SAT Math · Right triangles and trigonometry · hard

In a right triangle, the side opposite an acute angle has length x, and the hypotenuse has length x + 7. If the sine of that angle is 3/5,…

In a right triangle, the side opposite an acute angle has length xx, and the hypotenuse has length x+7x + 7. If the sine of that angle is 3/53/5, what is the value of xx?

Answer and explanation

Answer: 21/2 or 10.5

Sine is the ratio of the opposite side to the hypotenuse, so xx+7=35\frac{x}{x + 7} = \frac{3}{5}. Cross-multiply: 5x=3(x+7)=3x+215x = 3(x + 7) = 3x + 21. Subtract 3x3x: 2x=212x = 21, so x=212=10.5x = \frac{21}{2} = 10.5. Check: the hypotenuse is 17.517.5 and 10.517.5=0.6=35\frac{10.5}{17.5} = 0.6 = \frac{3}{5}. A common wrong answer is 7, which comes from ignoring the ratio and just reusing the number in the problem. Another is 4.2, from cross-multiplying incorrectly: 5x=3⋅7=215x = 3 \cdot 7 = 21, forgetting the xx in the denominator. Keep the full denominator x+7x + 7.

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