A regular hexagon has side length 6. Which value is closest to its area? (Area of a regular hexagon = 3√(3)2s²)

Substitute $s=6$ into the formula: $A=\frac{3\sqrt3}{2}(6^2)=\frac{3\sqrt3}{2}(36)=54\sqrt3$. Since $\sqrt3\approx1.732$, the area is $54(1.732)\approx93.5$, closest to $94$, choice D. Choice B ($187$) is double that value. Choice A ($62$) is two thirds of the correct value. Choice C ($108$) is $3\cdot36$, which uses $s^2$ but leaves out the factor $\frac{\sqrt3}{2}$. A check: a regular hexagon is six equilateral triangles, each of area $\frac{\sqrt3}{4}(36)\approx15.6$, and $6(15.6)\approx93.5$. Using the exact value $54\sqrt{3}$ avoids rounding errors until the last step.