A square has side length 10. A semicircle with diameter 10 is removed from one side. Which value is closest to the remaining area?

The remaining area is the square minus the semicircle. The square has area $10^2=100$. The semicircle has diameter $10$, so radius $5$ and area $\frac{1}{2}\pi(5)^2=\frac{25\pi}{2}\approx39.3$. The remaining area is $100-39.3\approx60.7$, closest to $61$, choice G. Choice F ($39$) is the semicircle's area alone. Choice H ($79$) is the area of a full circle of radius $5$, $25\pi\approx78.5$, not the semicircle. Choice J ($92$) subtracts an area that is too small. The remaining shape must be larger than half the square, but clearly less than $100$.