ACT Math · Number operations and exponents

What is (3.2 × 10^5)(2 × 10^-3)?

What is (3.2×105)(2×10−3)(3.2 \times 10^5)(2 \times 10^{-3})?

Answer and explanation

Answer: D: 6.4 × 10²

Multiply the coefficients and add the exponents of ten: (3.2)(2)=6.4(3.2)(2)=6.4 and 105⋅10−3=105+(−3)=10210^5\cdot10^{-3}=10^{5+(-3)}=10^2. The product is 6.4×1026.4\times10^2, choice D, which equals 640640; check: 320,000×0.002=640320{,}000\times0.002=640. Choice A adds the coefficients (3.2+2=5.23.2+2=5.2) instead of multiplying. Choice B treats 10−310^{-3} as 10310^3 and gets 10810^8. Choice C makes the exponent −2-2, as if subtracting 55 from 33 in the wrong direction. Negative exponents shrink the number, so the exponent after adding 55 and −3-3 must still be positive.

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