For the data set 3, 4, 5, 6, 50, how do the mean and median compare?

The mean is $\frac{3+4+5+6+50}{5}=\frac{68}{5}=13.6$. The median is the middle value of the ordered list, which is $5$. The mean is greater than the median, choice A. The extreme value $50$ pulls the mean upward, but it has no effect on the median because only its position at the end matters. Choice B reverses the comparison. Choice C would require a balanced data set. Choice D is false because the median of an odd number of values is simply the middle one. This is why a skewed data set has a mean pulled toward the long tail.