For x ≠ 4, which expression is equivalent to (x² - 16)/(x - 4)?

The numerator is a difference of squares: $x^2 - 16 = (x - 4)(x + 4)$. Then $\frac{(x-4)(x+4)}{x-4} = x + 4$, because the factor $x - 4$ cancels when $x \neq 4$. The answer is A. Choice B ($x - 4$) keeps the wrong factor. Choice C ($x^2 - 4$) comes from incorrectly dividing only the 16 term, canceling 4 from 16 but not from $x^2$ and $x$. Choice D ($x + 16$) comes from dividing $x^2$ by $x$ and leaving the 16 untouched. You can only cancel common factors, not individual terms of a sum or difference.