SAT Math · Equivalent expressions · medium

In the expansion of (x+5)(2x-3), what is the coefficient of the x term?

In the expansion of (x+5)(2x−3)(x+5)(2x-3), what is the coefficient of the xx term?

Answer and explanation

Answer: 7

Expand with FOIL: (x+5)(2x−3)=2x2−3x+10x−15=2x2+7x−15(x+5)(2x-3) = 2x^2 - 3x + 10x - 15 = 2x^2 + 7x - 15. The xx term is 7x7x, so the coefficient is 7. The middle term comes from the two cross products: the outer product x⋅(−3)=−3xx \cdot (-3) = -3x and the inner product 5⋅2x=10x5 \cdot 2x = 10x. A common wrong answer is 13, from adding 10+310 + 3 and ignoring the negative sign. Another is 2, the coefficient of x2x^2, and a third is −15-15, which is the constant term. Be careful to combine the cross terms with their signs.

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