SAT Math · Probability and conditional probability · medium

In a survey, 50% of respondents said they like coffee, 40% said they like tea, and 20% said they like both. What percent of respondents…

In a survey, 50% of respondents said they like coffee, 40% said they like tea, and 20% said they like both. What percent of respondents like coffee or tea (or both)?

Answer and explanation

Answer: A: 70%

Use the inclusion-exclusion formula: P(coffee or tea)=P(coffee)+P(tea)−P(both)P(\text{coffee or tea}) = P(\text{coffee}) + P(\text{tea}) - P(\text{both}). Substitute: 50%+40%−20%=70%50\% + 40\% - 20\% = 70\%, choice A. People who like both are counted in each of the first two percentages, so their share must be subtracted once. Choice B (90%) adds 50% and 40% without correcting for the overlap. Choice C (30%) is the share who like coffee only (50% minus 20%), and choice D (20%) is the share who like both. A Venn diagram makes this clear: 30% coffee only, 20% both, 20% tea only, total 70%.

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