SAT Math · Ratios, rates, proportional relationships, and units · easy

A physicist wants to compute the density of an object, defined as mass divided by volume. Which expression could represent a valid…

A physicist wants to compute the density of an object, defined as mass divided by volume. Which expression could represent a valid density, given a mass mm measured in kilograms and a volume VV measured in cubic meters?

Answer and explanation

Answer: A: m/V, in kilograms per cubic meter

Density is defined as mass per unit volume, which is mass divided by volume. With mm in kilograms and VV in cubic meters, the quotient mV\frac{m}{V} has units of kilograms per cubic meter, choice A. Choice B (mVmV) is a product, which would represent something like mass times volume, not a rate. Choice C (Vm\frac{V}{m}) is the reciprocal of density, called specific volume, and has units of cubic meters per kilogram. Choice D (m+Vm + V) adds quantities with different units, which is not meaningful because you cannot add kilograms to cubic meters. The units confirm the operation.

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