The graphs of y = x² + 2 and y = 6x - 4 intersect at two points. What is the sum of the x-coordinates of these two points?

Set the expressions equal: $x^2 + 2 = 6x - 4$, so $x^2 - 6x + 6 = 0$. The discriminant is $36 - 24 = 12 > 0$, confirming two intersection points. By Vieta's formulas, the sum of the roots is the negative of the $x$-coefficient: $-(-6) = 6$, choice A. Choice B (4) is not a result of any correct step. Choice C ($-6$) forgets to flip the sign. Choice D (2) is the constant in the first equation. The roots are irrational ($3 \pm \sqrt{3}$), so Vieta's formulas are much quicker than solving.