ACT Math study guide · Chapter 58
Additional Practice Test 1
This form follows a broadly balanced current-enhanced mix and rises in difficulty overall. It begins with quick core points, introduces more representation changes through the middle, and ends with several higher-demand items that require choosing a relationship before calculating. Local variation remains possible, so question position should guide pacing only broadly, not determine how much time any one item deserves.
Time: 50 minutes. Questions: 45. Calculator permitted throughout.
Work in order unless a question becomes locally expensive. Choose the best answer and move on when the route is not developing. Do not leave any question unanswered. A useful pacing checkpoint is roughly 15 questions complete by 14–16 minutes and roughly 30 complete by 31–34 minutes, preserving 16–19 minutes for the final 15.
▸ Questions
Question 1
- AA. $18
- BB. $47
- CC. $54
- DD. $60
Question 2
- FF. 7
- GG. 9
- HH. 11
- JJ. 13
Question 3
- AA. 10
- BB. 9
- CC. 11
- DD. 40
Question 4
- FF. 5
- GG. 1
- HH. 8
- JJ. 13
Question 5

- AA. 15
- BB. 13
- CC. 17
- DD. 25
Question 6
- FF. x¹⁵
- GG. x⁸
- HH. 2x⁸
- JJ. x²
Question 7
- AA. 224
- BB. 260
- CC. 336
- DD. 280
Question 8
- FF. x < −4
- GG. x > −4
- HH. x < 4
- JJ. x > 4
Question 9
- AA. (−4, −3)
- BB. (4, 3)
- CC. (−4, 3)
- DD. (3, 4)
Question 10
- FF. 10
- GG. 14
- HH. 18
- JJ. 24
Question 11
- AA. 1/3
- BB. 3/5
- CC. 1/4
- DD. 5/12
Question 12
- FF. 1
- GG. i
- HH. −i
- JJ. −1
Question 13

- AA. Its y-intercept is 1.
- BB. Its slope is 1/2.
- CC. It is decreasing.
- DD. It passes through (1, 1).
Question 14
- FF. 2w+3
- GG. 2w(w+3)
- HH. w(2w+3)
- JJ. w²+3
Question 15
- AA. 2
- BB. 25
- CC. √24
- DD. 5
Question 16
- FF. 12%
- GG. 13%
- HH. 15%
- JJ. 20%
Question 17
- AA. 0.125
- BB. √18
- CC. 7/9
- DD. √49
Question 18
- FF. The study method caused the difference in these volunteers.
- GG. The study method is effective for every student.
- HH. The groups were observational only.
- JJ. No causal conclusion is possible from random assignment.
Question 19
- AA. 5
- BB. 3
- CC. 4
- DD. 6
Question 20
- FF. (x−2)(x+5)
- GG. (x+2)(x+5)
- HH. (x+2)(x−5)
- JJ. (x−2)(x−5)
Question 21
- AA. 45 ft²
- BB. 270 ft²
- CC. 90 ft²
- DD. 540 ft²
Question 22
- FF. 2/5
- GG. 3/4
- HH. 5/3
- JJ. 4/5
Question 23
- AA. 9
- BB. 3
- CC. 6
- DD. 36
Question 24
- FF. 102
- GG. 97
- HH. 107
- JJ. 112
Question 25

- AA. 19
- BB. 27
- CC. 33
- DD. 13
Question 26
- FF. 1−i
- GG. 5+i
- HH. 1+5i
- JJ. 5−i
Question 27
- AA. 300
- BB. 200
- CC. 250
- DD. 500
Question 28
- FF. 0
- GG. 6
- HH. 3
- JJ. 9
Question 29

- AA. 60
- BB. 150
- CC. 96
- DD. 120
Question 30
- FF. 5.0
- GG. 7.5
- HH. 6.25
- JJ. 8.0
31. The table shows values of a linear function. What is f(10)?
| x | f(x) |
|---|---|
| 1 | 11 |
| 4 | 17 |
| 7 | 23 |
A) 23
B) 27
C) 31
D) 29
Question 32
- FF. 3π
- GG. 8π
- HH. 12π
- JJ. 6π
Question 33
- AA. 10
- BB. 25
- CC. 32
- DD. 64
Question 34
- FF. x−4
- GG. x+4
- HH. x²+4
- JJ. 1
Question 35
- AA. 1
- BB. 5
- CC. 2
- DD. 10
Question 36
- FF. 90π
- GG. 30π
- HH. 60π
- JJ. 180π
Question 37
- AA. $882
- BB. $828
- CC. $846
- DD. $936
Question 38
- FF. x=7 only
- GG. x=7 or x=−2
- HH. x=−2 only
- JJ. x=2 or x=−7
Question 39
- AA. 63
- BB. 96
- CC. 189
- DD. 192
Question 40
- FF. 10 sin40/sin65
- GG. 10 cos65/cos40
- HH. 10 tan65/tan40
- JJ. 10 sin65/sin40
Question 41
- AA. 49%
- BB. 52%
- CC. 55%
- DD. 57%
Question 42
- FF. (x−1)²(x−4)
- GG. (x+1)(x−4)(x−1)
- HH. (x−1)(x−2)²
- JJ. (x+1)(x−2)(x+2)
Question 43

- AA. 3
- BB. 21
- CC. 18
- DD. 36
Question 44
- FF. 24
- GG. 18
- HH. 30
- JJ. 37.5
Question 45
- AA. 1/2
- BB. −1/2
- CC. 2
- DD. −2
▸ Answers and Explanations
Show the answers and explanations
1: C. A 25% discount means paying 75% of the original price: 72(0.75)=$54. The requested object is the final sale price, not the discount amount.
2: G. Add 7 to both sides: 3x=27, so x=9.
3: A. The sum is 40 and there are 4 values, so the mean is 40/4=10.
4: F. Substitute x=2: 2(2²)−3=8−3=5.
5: B. By the Pythagorean theorem: c=√(5²+12²)=√169=13.
6: G. For the same base, add exponents when multiplying: x^(3+5)=x⁸.
7: D. The unit rate is 168/3=56 miles per hour. In 5 hours the car travels 56(5)=280 miles.
8: F. Subtract 5 from both sides: −2x>8. Dividing by −2 reverses the inequality: x<−4.
9: B. Reflecting across the x-axis keeps x the same and changes the sign of y: (4,−3)→(4,3).
10: H. Evaluate inside first: g(2)=2+4=6. Then h(6)=3(6)=18.
11: C. There are 12 marbles total and 3 are blue, so P(blue)=3/12=1/4.
12: J. Powers of i repeat every 4. Since 18 leaves remainder 2 when divided by 4, i¹⁸=i²=−1.
13: A. In slope-intercept form y=mx+b, the y-intercept is b=1. The slope is 2, so the graph increases, and at x=1 the y-value is 3, not 1.
14: H. Length=2w+3, so area=width×length=w(2w+3). This is a setup item; do not calculate a number that was never asked for.
15: D. Circle form is (x−h)²+(y−k)²=r². Here r²=25, so r=5.
16: H. The increase is 92−80=12. Dividing by the original value: 12/80=0.15=15%.
17: B. √18=3√2, which is irrational since 18 is not a perfect square. The other three values are all rational.
18: F. Random assignment supports a causal conclusion for this study's sample. It does not automatically justify generalizing to every student, since the volunteers were not described as a random sample of all students.
19: A. Adding the two equations eliminates y: 3x=15, so x=5.
20: H. A zero at −2 gives the factor (x+2); a zero at 5 gives the factor (x−5).
21: B. The actual dimensions are 2.5(6)=15 ft and 3(6)=18 ft. Area=15×18=270 ft². A common error is applying the linear scale factor only once to an area calculation.
22: J. Using sin²θ+cos²θ=1: cos²θ=1−9/25=16/25, so cosθ=4/5 (positive for an acute angle).
23: A. Exactly one real solution means the discriminant equals 0: (−6)²−4(1)(k)=0, so 36−4k=0, giving k=9.
24: F. aₙ=a₁+(n−1)d: a₂₀=7+19(5)=7+95=102.
25: D. IQR=Q3−Q1=31−18=13.
26: J. Distribute: (3+2i)(1−i)=3−3i+2i−2i²=3−i+2=5−i.
27: A. Set the costs equal: 25+0.08t=40+0.03t. Then 0.05t=15, so t=300.
28: G. Factor: (x−3)(x+3)/(x−3)=x+3 for x≠3. The missing point occurs at x=3, giving y=3+3=6.
29: B. The linear scale factor is 15/6=2.5. Area scales by the square of that factor: 24(2.5²)=24(6.25)=150.
30: H. Scale by 20/8=2.5: 2.5 cups × 2.5=6.25 cups.
31: D. From the table, y increases by 6 when x increases by 3, so the slope is 2. Using the point (1,11): f(x)=2x+9. Thus f(10)=2(10)+9=29.
32: J. Arc length=(135/360)(2π·8)=(3/8)(16π)=6π.
33: C. log₂(x)=5 means 2⁵=x, so x=32.
34: G. Factor the numerator: (x−4)(x+4). Cancel x−4 for x≠4, leaving x+4.
35: C. z=(80−70)/5=10/5=2.
36: F. V=πr²h=π(3)²(10)=90π.
37: A. Regular pay=40(18)=720. Overtime rate=1.5(18)=27, and overtime pay=6(27)=162. Total=720+162=882.
38: G. Two cases: 2x−5=9 gives x=7; 2x−5=−9 gives x=−2.
39: C. The terms are 3,6,12,24,48,96. Their sum is 189, which also follows from Sₙ=a(1−rⁿ)/(1−r).
40: J. By the Law of Sines, a/sin A=b/sin B. Solving for b gives b=10 sin(65°)/sin(40°).
41: D. The plausible interval is 52%−4%=48% to 52%+4%=56%. Since 57% lies outside that interval, it is the value not consistent with the reported margin of error.
42: G. Factor by grouping: x²(x−4)−1(x−4)=(x²−1)(x−4)=(x−1)(x+1)(x−4).
43: C. The function is in vertex form. The vertex is (3,18), and since the leading coefficient is negative, this vertex is a maximum. Maximum height=18 feet.
44: F. Full volume=4×3×2.5=30 ft³. At 80% full: 0.8(30)=24 ft³.
45: B. The radius from the origin to (2,4) has slope 4/2=2. A tangent line is perpendicular to the radius at the point of tangency, so its slope is the negative reciprocal, −1/2.