If f(x) = x² and g(x) = f(x-3) + 2, what is g(5)?

Substitute into the definition: $g(5)=f(5-3)+2=f(2)+2=2^2+2=6$, choice D. Choice A ($4$) forgets the outer $+2$ and stops at $f(2)=4$. Choice C ($27$) ignores the horizontal shift and computes $f(5)+2=25+2=27$. Choice B ($66$) shifts in the wrong direction, using $f(5+3)+2=64+2=66$. Remember that $f(x-3)$ means you subtract 3 from the input before squaring, and any number added outside the function is added at the very end, after the squaring is done. Writing out each step this way makes the order of operations clear.