ACT Math · Number operations and exponents

What is (8 × 10^7) ÷ (2 × 10^-2)?

What is (8×107)÷(2×10−2)(8 \times 10^7) \div (2 \times 10^{-2})?

Answer and explanation

Answer: D: 4 × 10^9

Divide the coefficients and subtract the exponents of ten: 82=4\frac{8}{2}=4 and 107÷10−2=107−(−2)=10910^{7}\div10^{-2}=10^{7-(-2)}=10^{9}. The quotient is 4×1094\times10^9, choice D. Choice A (4×1054\times10^5) subtracts the exponents as 7−27-2, ignoring the negative sign. Choice C (4×10−94\times10^{-9}) has the exponent's sign wrong. Choice B (1.6×1091.6\times10^9) multiplies the coefficients (8⋅2=168\cdot2=16) instead of dividing them. Division by a very small number makes the quotient larger, so the exponent should increase, to 99. A quick estimate, 80,000,0000.02\frac{80{,}000{,}000}{0.02}, is four billion.

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