Solve for x: √(2x - 3) = 5.

Square both sides to remove the radical: $2x-3=25$. Add $3$: $2x=28$. Divide by $2$: $x=14$, choice A. Always check for extraneous solutions when squaring: $\sqrt{2(14)-3}=\sqrt{25}=5$, which is correct. Choice D ($28$) stops at $2x=28$ and does not divide by $2$. Choice B ($11$) subtracts $3$ instead of adding it: $\frac{25-3}{2}=11$, which gives $\sqrt{19}$, not $5$. Choice C ($4$) does not work: $\sqrt{2(4)-3}=\sqrt5$, not $5$. Squaring can introduce extra roots, so the check is always needed.