What are the solutions to 2x² - 7x - 15 = 0?

Factor $2x^2-7x-15$ as $(2x+3)(x-5)$, then set each factor to zero: $x=-\frac{3}{2}=-1.5$ or $x=5$, choice A. The quadratic formula agrees: the discriminant is $49+120=169$, so $x=\frac{7\pm13}{4}$, giving $5$ and $-1.5$. Check with the sum of the roots, which must equal $\frac{7}{2}=3.5$: $5+(-1.5)=3.5$. Choice B flips the sign of both roots. Choice C gets one root right but gives the other as $+1.5$ (sum $6.5$). Choice D has the correct product ($-7.5$) but its sum is $0.5$, not $3.5$, so it does not satisfy the equation.