Solve the system: 3x + 2y = 16 and x + 4y = 22. What is the value of x?

Multiply the first equation by $2$ to match the $y$ coefficients: $6x+4y=32$. Subtract the second equation, $x+4y=22$: $5x=10$, so $x=2$. Then $2+4y=22$ gives $y=5$. Check in the first equation: $3(2)+2(5)=16$. So $x=2$, choice F. Choice H ($5$) is the value of $y$. Choice G ($4$) and choice J ($8$) do not work: for $x=4$ the first equation gives $y=2$, but then $4+8=12\ne22$. Always make sure the answer is the variable the question asks about.