SAT Math · Linear equations in one variable · medium

A coffee shop blends a 8-per-pound coffee with a 14-per-pound coffee to create 20 pounds of a blend costing 11 per pound. How many pounds…

A coffee shop blends a $8-per-pound coffee with a $14-per-pound coffee to create 20 pounds of a blend costing $11 per pound. How many pounds of the $14 coffee are needed?

Answer and explanation

Answer: C: 10

Let bb be the pounds of the $14 coffee, so 20−b20 - b pounds of the $8 coffee. The total cost of the blend is 8(20−b)+14b=11(20)8(20 - b) + 14b = 11(20). Simplify: 160−8b+14b=220160 - 8b + 14b = 220, so 6b=606b = 60 and b=10b = 10, choice C. Sanity check: $11 is exactly halfway between $8 and $14, so the two coffees are used in equal amounts. Choice A (12) and choice B (8) give prices of $11.60 and $10.40. Choice D (15) gives a blend costing $12.50 per pound. Check the weighted price.

More Linear equations in one variable questions

All Linear equations in one variable questions

Learn the method behind questions like this one

The SAT Math course teaches each tested skill through lessons, step-by-step solutions to sample problems, the complete study guide and full-length practice tests.