What is the value of x if (4x-3)/(7) + 2 = 9?

Undo the operations in reverse order. Subtract 2 from both sides of $\frac{4x - 3}{7} + 2 = 9$: $\frac{4x - 3}{7} = 7$. Multiply by 7: $4x - 3 = 49$. Add 3: $4x = 52$. Divide by 4: $x = 13$, choice D. Check: $\frac{4(13) - 3}{7} + 2 = \frac{49}{7} + 2 = 9$. Choice A (11) gives $\frac{41}{7} + 2 \approx 7.9$. Choice B (15) gives $\frac{57}{7} + 2 \approx 10.1$. Choice C (9) gives $\frac{33}{7} + 2 \approx 6.7$. None satisfies the equation, so back-substitution quickly rules them out.