SAT Math · Nonlinear functions · medium

A company's daily profit, in dollars, is modeled by P(x) = -3x² + 150x - 800, where x is the number of units sold. How many units should…

A company's daily profit, in dollars, is modeled by P(x)=−3x2+150x−800P(x) = -3x^2 + 150x - 800, where xx is the number of units sold. How many units should be sold to maximize profit?

Answer and explanation

Answer: 25

The profit function P(x)=−3x2+150x−800P(x) = -3x^2 + 150x - 800 is a downward-opening parabola, so its maximum is at the vertex. The vertex has x=−b2a=−1502(−3)=25x = -\frac{b}{2a} = -\frac{150}{2(-3)} = 25 units. The constant −800-800 shifts the profit up or down but does not change where the maximum occurs. The maximum profit is P(25)=−1875+3750−800=1075P(25) = -1875 + 3750 - 800 = 1075 dollars. A common wrong answer is 1075, which is the maximum profit rather than the number of units. Another is 50, from using −ba-\frac{b}{a}, forgetting to double the denominator. Answer the quantity asked.

More Nonlinear functions questions

All Nonlinear functions questions

Learn the method behind questions like this one

The SAT Math course teaches each tested skill through lessons, step-by-step solutions to sample problems, the complete study guide and full-length practice tests.