SAT Math · Nonlinear functions · easy

The function f is defined by f(x) = (x+5)(x-9). What is the sum of the zeros of f?

The function ff is defined by f(x)=(x+5)(x−9)f(x) = (x+5)(x-9). What is the sum of the zeros of ff?

Answer and explanation

Answer: 4

The zeros of f(x)=(x+5)(x−9)f(x) = (x + 5)(x - 9) are the values that make a factor zero: x=−5x = -5 and x=9x = 9. Their sum is −5+9=4-5 + 9 = 4. Check by expanding: f(x)=x2−4x−45f(x) = x^2 - 4x - 45, and the sum of the roots is −−41=4-\frac{-4}{1} = 4. A common wrong answer is −4-4, which comes from adding the numbers in the factors, 5+(−9)5 + (-9), instead of the zeros, whose signs are opposite. Another is −45-45, which is the product of the zeros. Read zeros from the factors with the opposite sign.

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