SAT Math · Nonlinear functions · easy

What is the equation of the vertical asymptote of f(x) = (2x+9)/(x-4)?

What is the equation of the vertical asymptote of f(x)=2x+9x−4f(x) = \dfrac{2x+9}{x-4}?

Answer and explanation

Answer: B: x=4

The vertical asymptote of a rational function occurs where the denominator is zero and the numerator is nonzero. Set x−4=0x - 4 = 0 to get x=4x = 4. The numerator there is 2(4)+9=172(4) + 9 = 17, which is not zero, so there is a vertical asymptote at x=4x = 4, choice B. Choice A (x=−4x = -4) has the wrong sign. Choice C (x=9x = 9) uses the constant term of the numerator. Choice D (y=2y = 2) is the horizontal asymptote, the ratio of leading coefficients, and is not vertical.

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