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What is the maximum value of the function f(x) = -x² + 10x - 21?

What is the maximum value of the function f(x)=−x2+10x−21f(x) = -x^2 + 10x - 21?

Answer and explanation

Answer: A: 4

Complete the square: −x2+10x−21=−(x2−10x)−21=−(x2−10x+25)+25−21=−(x−5)2+4-x^2 + 10x - 21 = -(x^2 - 10x) - 21 = -(x^2 - 10x + 25) + 25 - 21 = -(x - 5)^2 + 4. Because of the negative sign, the parabola opens downward and its highest point is the vertex (5,4)(5, 4). The maximum value is 4, choice A. Check by plugging in: f(5)=−25+50−21=4f(5) = -25 + 50 - 21 = 4. Choice B (−21-21) is the yy-intercept. Choice C (5) is where the maximum occurs, the xx-coordinate. Choice D (10) is the xx-coefficient. The maximum value is the output, not the input.

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