For x ≠ 2 and x ≠ -2, which expression is equivalent to (x^4 - 16)/(x² - 4)?

Factor the numerator as a difference of squares twice: $x^4 - 16 = (x^2 - 4)(x^2 + 4)$. The denominator is $x^2 - 4$, so the common factor cancels (valid since $x \neq \pm 2$), leaving $x^2 + 4$, choice A. Choice B ($x^2 - 4$) keeps the wrong factor. Choice C ($x^2 + 16$) comes from dividing only the first term of the numerator by the denominator's first term and ignoring the rest. Choice D ($x + 4$) takes the square root of the terms, which is not a legitimate step. Only common factors can be canceled.