SAT Math · Equivalent expressions · medium

When the polynomial x³ - 2x² + 5 is divided by x - 1, what is the remainder?

When the polynomial x3−2x2+5x^3 - 2x^2 + 5 is divided by x−1x - 1, what is the remainder?

Answer and explanation

Answer: 4

By the remainder theorem, the remainder when a polynomial p(x)p(x) is divided by x−ax - a is p(a)p(a). Here a=1a = 1, so the remainder is p(1)=13−2(1)2+5=1−2+5=4p(1) = 1^3 - 2(1)^2 + 5 = 1 - 2 + 5 = 4. You can verify with synthetic division using coefficients 1, −2-2, 0, 5: bring down 1; then −2+1=−1-2 + 1 = -1; then 0+(−1)=−10 + (-1) = -1; then 5+(−1)=45 + (-1) = 4. The last number, 4, is the remainder. A common wrong answer is 2, which comes from evaluating at x=−1x = -1 instead of x=1x = 1. Another is 5, from dropping the other terms. Evaluate at the root of the divisor, which is +1+1.

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