SAT Math · Linear equations in one variable · medium

A square has a side length of 2x + 3. If the perimeter of the square is 68, what is the value of x?

A square has a side length of 2x+32x + 3. If the perimeter of the square is 68, what is the value of xx?

Answer and explanation

Answer: D: 7

The perimeter of a square is 4 times its side length, so 4(2x+3)=684(2x + 3) = 68. Divide by 4: 2x+3=172x + 3 = 17. Subtract 3: 2x=142x = 14, so x=7x = 7, choice D. Check: the side is 17, and 4×17=684 \times 17 = 68. Choice A (8) gives a side of 19. Choice B (14.5) gives a side of 32 and a perimeter of 128. Choice C (6) gives a side of 15 and a perimeter of 60. Choice D is the only value that makes the perimeter exactly 68. Remember the side is 2x+32x + 3, not xx.

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