SAT Math · Nonlinear equations in one variable · hard

The equation x² - 9x + c = 0 has two real solutions that differ by 5. What is the value of c?

The equation x2−9x+c=0x^2 - 9x + c = 0 has two real solutions that differ by 5. What is the value of cc?

Answer and explanation

Answer: 14

Let the roots be rr and r+5r + 5. The sum of the roots of x2−9x+c=0x^2 - 9x + c = 0 is 9, so r+(r+5)=9r + (r + 5) = 9, giving 2r=42r = 4 and r=2r = 2. The roots are 2 and 7. The product of the roots equals cc, so c=2×7=14c = 2 \times 7 = 14. Verify: x2−9x+14=(x−2)(x−7)x^2 - 9x + 14 = (x - 2)(x - 7), and 7−2=57 - 2 = 5. A common wrong answer is 20, from using the roots 4 and 5, which sum to 9 but differ by only 1. Another is 9, the sum of the roots, which is the coefficient and not cc.

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