What is the solution to (3x+1)/(x-4) = 2, given that x ≠ 4?

Multiply both sides by $x - 4$ (allowed because $x \neq 4$): $3x + 1 = 2(x - 4) = 2x - 8$. Subtract $2x$ and 1 from both sides: $x = -9$, choice B. Check: $\frac{3(-9) + 1}{-9 - 4} = \frac{-26}{-13} = 2$. Choice A (4) is the excluded value that makes the denominator zero. Choice C (9) has the wrong sign and gives $\frac{28}{5} \neq 2$. Choice D ($-1$) comes from solving $3x + 1 = 2x$ without distributing the 2 over $x - 4$, which ignores the $-8$. Distribute fully before collecting terms.