SAT Math · Nonlinear functions · hard

A quantity triples every 6 years. What is the growth factor for a 2-year period, rounded to the nearest hundredth?

A quantity triples every 6 years. What is the growth factor for a 2-year period, rounded to the nearest hundredth?

Answer and explanation

Answer: 1.44

If a quantity triples every 6 years, let rr be the growth factor per 2 years. Three 2-year periods make up 6 years, so r3=3r^3 = 3 and r=31/3≈1.4422r = 3^{1/3} \approx 1.4422. Rounded to the nearest hundredth, the answer is 1.44. Check: 1.443≈2.991.44^3 \approx 2.99. A common wrong answer is 1.50, which comes from dividing 3÷23 \div 2. Another is 1.33, from splitting the 200% increase into thirds as if growth were linear (1+231 + \frac{2}{3}). A third is 1.73, which is 3\sqrt{3} and applies to a 3-year period rather than a 2-year period. Exponential growth is handled by roots, not division.

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