SAT Math · Systems of two linear equations in two variables · medium

The system of equations 2x + 5y = 10 and 6x + ky = 30 has infinitely many solutions. What is the value of k?

The system of equations 2x+5y=102x + 5y = 10 and 6x+ky=306x + ky = 30 has infinitely many solutions. What is the value of kk?

Answer and explanation

Answer: C: 15

A system has infinitely many solutions when the two equations describe the same line, so the second must be a constant multiple of the first. Comparing the xx-coefficients, 6=3⋅26 = 3 \cdot 2, and comparing the constants, 30=3⋅1030 = 3 \cdot 10, so the multiplier is 3. The yy-coefficient must then be 3⋅5=153 \cdot 5 = 15, so k=15k = 15, choice C. Choice A (5) copies the original yy-coefficient without scaling. Choice B (10) copies the constant. Choice D (18) results from multiplying by the wrong factor, such as 6⋅36 \cdot 3. Any value other than 15 gives either one solution or none.

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