If f(x) = (x²-9)/(x-3), what is f(5)?

Substitute $x=5$ directly: $f(5)=\frac{25-9}{5-3}=\frac{16}{2}=8$, choice H. Alternatively, factor the numerator: $\frac{(x-3)(x+3)}{x-3}=x+3$ for $x\ne3$, and $5+3=8$. Choice J ($16$) is the numerator alone, forgetting to divide by $2$. Choice G ($4$) is $\frac{16}{4}$, a mistake with the denominator. Choice F ($2$) is the denominator alone. The value $x=5$ is not the excluded value $x=3$, so the function is defined there. Both methods agree, which is a good way to confirm the result when the function simplifies.