A linear function h satisfies h(-2) = 10 and h(3) = 0. What is the value of h(6)?

Find the slope from the two known points: $\frac{0 - 10}{3 - (-2)} = \frac{-10}{5} = -2$. From $x = 3$ to $x = 6$, the input increases by 3, so the output changes by $-2 \times 3 = -6$. Therefore $h(6) = 0 - 6 = -6$, choice B. Choice A ($-4$) adds the slope twice, using a change of 2 in $x$. Choice C (2) has the wrong sign on the slope. Choice D ($-10$) is the change from $x = -2$ to $x = 3$ and is not the value at 6. Always multiply the slope by the full change in $x$ from a known point.