What is the solution set of the system x > -3, x ≤ 5, and 2x - 1 < 9?

Solve the third inequality first: $2x - 1 < 9$ gives $2x < 10$, so $x < 5$. All three conditions must hold at once: $x > -3$, $x \leq 5$, and $x < 5$. The upper limits $x \leq 5$ and $x < 5$ overlap, and the stricter one wins, since $x = 5$ fails $x < 5$. The solution is $-3 < x < 5$, choice B. Choice A keeps $x \leq 5$, which wrongly allows $x = 5$. Choice C ($x < 5$) drops the lower bound. Choice D uses 9, which is the right side of the third inequality before solving, an unfinished step.