Which statement is true about the graph of y ≤ 3x - 2?

The symbol $\leq$ includes equality, so points on the line $y = 3x - 2$ satisfy the inequality and the boundary is drawn solid. A dashed boundary is used only for strict inequalities such as $<$ or $>$. Now test $(0,0)$: is $0 \leq 3(0) - 2 = -2$? No, since $0$ is greater than $-2$. So $(0,0)$ is not a solution, and the graph shades the side below the line, which does not contain the origin. That makes C correct. Choices A and D claim a dashed line, which is wrong. Choice B has a solid line but wrongly says $(0,0)$ works.