SAT Math · Systems of two linear equations in two variables · easy

The system 4x + ky = 48 and 2x - y = 8 has solution (6, 4). What is the value of k?

The system 4x+ky=484x + ky = 48 and 2x−y=82x - y = 8 has solution (6,4)(6, 4). What is the value of kk?

Answer and explanation

Answer: 6

The solution (6,4)(6, 4) must satisfy both equations. Check the second: 2(6)−4=82(6) - 4 = 8. Substitute into the first: 4(6)+k(4)=484(6) + k(4) = 48, so 24+4k=4824 + 4k = 48, then 4k=244k = 24 and k=6k = 6. A common wrong answer is 24, which is the value of 4k4k and not kk. Another is 12, from 484\frac{48}{4}, which ignores the 4x4x term. A third is 4, the value of yy. Always substitute into the equation that includes the unknown, then divide by its coefficient.

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