SAT Math · Linear inequalities in one or two variables · medium

For the system x > k and x < 10 to have at least one solution, k must be less than what value?

For the system x>kx > k and x<10x < 10 to have at least one solution, kk must be less than what value?

Answer and explanation

Answer: 10

The system x>kx > k and x<10x < 10 asks for numbers that are greater than kk and less than 10 at the same time. Such numbers exist only if there is room between kk and 10, which means k<10k < 10. If k=10k = 10, the conditions become x>10x > 10 and x<10x < 10, which no number satisfies. If k>10k > 10, the situation is even worse. So kk must be less than 10. A common wrong answer is 9, which assumes an integer solution is required, but the problem does not say so; for k=9.5k = 9.5, the value x=9.7x = 9.7 works. The strict inequalities mean k=10k = 10 itself fails, but any kk below 10 works.

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