Which of the following is equivalent to -2(x-3) > 10?

Distribute: $-2(x - 3) = -2x + 6$, so the inequality is $-2x + 6 > 10$. Subtract 6: $-2x > 4$. Divide both sides by $-2$ and reverse the inequality sign: $x < -2$, choice B. Test $x = -3$: $-2(-6) = 12 > 10$, which is true. Choice A ($x > -2$) divides by $-2$ but fails to reverse the sign. Choices C ($x < 8$) and D ($x > 8$) do not follow from valid steps: $x = 0$ fails $-2(x-3) > 10$ because $6 < 10$, and $x = 9$ fails because $-12 < 10$. Multiplying or dividing by a negative flips the inequality.