SAT Math · Linear inequalities in one or two variables · hard

For x ≥ 0 and y ≥ 0 satisfying 2x + y ≤ 14 and x + 3y ≤ 17, what is the greatest possible value of 3x + 2y?

For x≥0x \geq 0 and y≥0y \geq 0 satisfying 2x+y≤142x + y \leq 14 and x+3y≤17x + 3y \leq 17, what is the greatest possible value of 3x+2y3x + 2y?

Answer and explanation

Answer: C: 23

The maximum of a linear expression over a bounded region occurs at a vertex. The constraints x,y≥0x, y \geq 0, 2x+y≤142x + y \leq 14, and x+3y≤17x + 3y \leq 17 give vertices (0,0)(0, 0), (7,0)(7, 0), (0,173)(0, \frac{17}{3}), and the intersection of the lines. From y=14−2xy = 14 - 2x into x+3y=17x + 3y = 17: x+42−6x=17x + 42 - 6x = 17, so x=5x = 5 and y=4y = 4. Evaluate 3x+2y3x + 2y: 0, 21, 343≈11.3\frac{34}{3} \approx 11.3, and 15+8=2315 + 8 = 23. The maximum is 23, choice C. Choice B (21) is the value at (7,0)(7, 0) only. Choices A (28) and D (25) are not achieved by any vertex.

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