SAT Math · Linear inequalities in one or two variables · medium

A parking lot must hold no fewer than 50 cars and no more than 120 cars at any time. What is the width of the range of possible numbers of…

A parking lot must hold no fewer than 50 cars and no more than 120 cars at any time. What is the width of the range of possible numbers of cars in the lot?

Answer and explanation

Answer: A: 70

The condition "no fewer than 50 and no more than 120" is the compound inequality 50≤c≤12050 \leq c \leq 120. The width of a range is the difference between the maximum and the minimum: 120−50=70120 - 50 = 70, choice A. Choice B (120) is the maximum number of cars. Choice C (50) is the minimum number of cars. Choice D (170) comes from adding the two limits, 50+12050 + 120. Width asks how far apart the endpoints are, which is a subtraction. For example, if the lot holds 60 cars, that is 10 above the minimum, and the range covers 70 possible additional cars from bottom to top.

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